3[2(x+1)-x]=5(x+2)

Solution for 3[2(x+1)-x]=5(x+2) equation:

Simplifying
3[2(x + 1) + -1x] = 5(x + 2)

Reorder the terms:
3[2(1 + x) + -1x] = 5(x + 2)
3[(1 * 2 + x * 2) + -1x] = 5(x + 2)
3[(2 + 2x) + -1x] = 5(x + 2)

Combine like terms: 2x + -1x = 1x
3[2 + 1x] = 5(x + 2)
[2 * 3 + 1x * 3] = 5(x + 2)
[6 + 3x] = 5(x + 2)

Reorder the terms:
6 + 3x = 5(2 + x)
6 + 3x = (2 * 5 + x * 5)
6 + 3x = (10 + 5x)

Solving
6 + 3x = 10 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.
6 + 3x + -5x = 10 + 5x + -5x

Combine like terms: 3x + -5x = -2x
6 + -2x = 10 + 5x + -5x

Combine like terms: 5x + -5x = 0
6 + -2x = 10 + 0
6 + -2x = 10

Add '-6' to each side of the equation.
6 + -6 + -2x = 10 + -6

Combine like terms: 6 + -6 = 0
0 + -2x = 10 + -6
-2x = 10 + -6

Combine like terms: 10 + -6 = 4
-2x = 4

Divide each side by '-2'.
x = -2

Simplifying
x = -2